Now the remaining knapsack capacity is 14 and our selection is 1 means selected Then we have the next profitable item is item no. Now the remaining knapsack capacity is 8 and our selection is 1 means selected Then we have the next profitable item is item no.
Now the remaining knapsack capacity is 6 and our selection is 1 means selected Then we have the next profitable item is item no. Now the remaining knapsack capacity is 4 and our selection is 1 means selected Then we have the next profitable item is item no. View All. Khushbu Saini Updated date Aug 31, Hi guys! The first profitable item we have are item no. Then we have the next profitable item is item no. Display the sorted table Print the arrays p[] ,w[] and ratio[] Calculate Solution array x[] For each weight in w[] that is less than or equal to the value of u ie.
Now, let's see the actual code for all these steps. This article and the code were written by Nived Kannada. Follow on Instagram to show your support. No comments:. Older Post Home. In this Are you finding it difficult to understand the logic of Banker's algorithm? Are you struggling to simulate Banker's algorithm usin We will also have a real-world implementation using Java program.
The knapsack problem is an optimization problem or a maximization problem. It is also known as the Container loading problem. We have some objects and every object is having some weights, We are provided with a bag that bag is known as Knapsack We have to fill the maximum objects in the bag according to their weights and profit so that the profit we get is maximum.
We will be provided by the object identification including their profits and weight. The total weight of the objects filled in the bags should be less than the provided counter m which is given.
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